2x - 5y = 16 \\
3x + 2y = 5
\end{cases}

Let’s solve them step by step.

Step 1: Eliminate one variable

Multiply the first equation by 2 and the second by 5 so the terms match:

\begin{aligned}
4x - 10y &= 32 \\
15x + 10y &= 25
\end{aligned}

Step 2: Add the equations

(4x - 10y) + (15x + 10y) = 32 + 25

19x = 57

x = 3

Step 3: Substitute into one equation

Using :

3(3) + 2y = 5

9 + 2y = 5

2y = -4

y = -2


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✅ Final Answer:

\boxed{x = 3,\; y = -2}

If you want, I can also show a substitution method or explain it in a more exam-friendly way 📘✨