Mathematic waec and jamb question - Bondhuu

Mathematic waec and jamb question

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By Ayodex on Jan 21, 2026

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Adamsdon

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Bro jonah a-z God's love

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5 days, 17 hours ago

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Pls any update on jamb
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Ayodex

If log10^(6x-4) - log10^2 = 1,find x solution log10^6x-4/2 =log10^10^1 log10 cancel log10 6x-4/2=10 cross multiply 6x-4=10×2 6x-4=20 collect like term 6x=20+4 6x=24 divide both sides by 6 x=24/6 x=4

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Bro jonah a-z God's love

Bro jonah a-z God's love

1 week ago

I'm Here For waec tutoria
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Ok

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ok should i message you private

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I will so much love it
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Bianca

Wat are they waiting 4 then

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Me too

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